x-1/2(8-x)=x+3(4x)-x

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Solution for x-1/2(8-x)=x+3(4x)-x equation: 



x-1/2(8-x)=x+3(4x)-x

We move all terms to the left:

x-1/2(8-x)-(x+3(4x)-x)=0



Domain of the equation: 2(8-x)!=0

x∈R



We add all the numbers together, and all the variables

x-1/2(-1x+8)-(+34x)=0

We get rid of parentheses

x-1/2(-1x+8)-34x=0

We multiply all the terms by the denominator


x*2(-1x+8)-34x*2(-1x+8)-1=0

Wy multiply elements

2x^2(--68x^2(--1=0

We use the square of the difference formula

2x^2(+68x^2(+1=0

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