If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
x-(1/3)-4 = x-(9/4) // - x-(9/4)
x-x-(1/3)+9/4-4 = 0
x-x-1/3+9/4-4 = 0
-25/12 = 0
x belongs to the empty set
x belongs to the empty set
| Y=4(-3)+4 | | 10+10x=10+10x | | X-2/3=42/5 | | -8x-7=-9x+1 | | 10x+5y-2= | | 0=9x+39x+12 | | 4x+4=-4x-20 | | (1+6i)(1+6i)=0 | | 10/56 | | -[6z-(17z+4)]=4+(10z+1) | | 7t-12=-2+5t | | 2x^2+3=131 | | 8m^2-10=118 | | 4p^2-15p-25= | | 2[t-(2t+11)+10]=2(t+1) | | 3x^2-2x+1=-3x^2+9x+11 | | 0.6k+0.08k=44+8 | | -2p-4(3-3p)=6(p-4)-8 | | 36-4x=5x-9 | | -.333333x+1.33333y=-2.33333 | | x-3/5=5/12 | | 6y-7=-11+4y | | 6k^2+13k+2= | | 7÷7/4 | | -3+12=4 | | -m^2-7m+6=0 | | M^2+7m-6=0 | | 6p^2+17p+12= | | X^-1/2=9 | | 3(x-2)=7x+4-2x | | 4x^2+40x+91=0 | | 12x^2+81x+54= |