x-1/3=1/6(2x-5)

Solution for x-1/3=1/6(2x-5) equation:

x-1/3=1/6(2x-5)

We move all terms to the left:

x-1/3-(1/6(2x-5))=0


Domain of the equation: 6(2x-5))!=0

x∈R


We calculate fractions


x+()/36x+(-6x2/36x=0

We multiply all the terms by the denominator


x*36x+(-6x2+()=0


We calculate terms in parentheses: +(-6x2+(), so:

-6x2+(

We add all the numbers together, and all the variables

-6x^2

Back to the equation:

+(-6x^2)


Wy multiply elements

(-6x^2)+36x^2=0

We get rid of parentheses

-6x^2+36x^2=0

We add all the numbers together, and all the variables

30x^2=0

a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{60}=0$