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x-1/3x-12=1/2x
We move all terms to the left:
x-1/3x-12-(1/2x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-1/3x-(+1/2x)-12=0
We get rid of parentheses
x-1/3x-1/2x-12=0
We calculate fractions
x+(-2x)/6x^2+(-3x)/6x^2-12=0
We multiply all the terms by the denominator
x*6x^2+(-2x)+(-3x)-12*6x^2=0
Wy multiply elements
6x^3-72x^2+(-2x)+(-3x)=0
We get rid of parentheses
6x^3-72x^2-2x-3x=0
We do not support expression: x^3
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