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x-1/3x=112
We move all terms to the left:
x-1/3x-(112)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
x*3x-112*3x-1=0
Wy multiply elements
3x^2-336x-1=0
a = 3; b = -336; c = -1;
Δ = b2-4ac
Δ = -3362-4·3·(-1)
Δ = 112908
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112908}=\sqrt{37636*3}=\sqrt{37636}*\sqrt{3}=194\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-336)-194\sqrt{3}}{2*3}=\frac{336-194\sqrt{3}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-336)+194\sqrt{3}}{2*3}=\frac{336+194\sqrt{3}}{6} $
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