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x-1/4(12-x)=x+3(4-x)-2x
We move all terms to the left:
x-1/4(12-x)-(x+3(4-x)-2x)=0
Domain of the equation: 4(12-x)!=0We add all the numbers together, and all the variables
x∈R
x-1/4(-1x+12)-(x+3(-1x+4)-2x)=0
We multiply all the terms by the denominator
x*4(-1x+12)-((x+3(-1x+4)-2x))*4(-1x+12)-1=0
We calculate terms in parentheses: -((x+3(-1x+4)-2x))*4(-1x+12), so:We add all the numbers together, and all the variables
(x+3(-1x+4)-2x))*4(-1x+12
We add all the numbers together, and all the variables
-1x+(x+3(-1x+4)-2x))*4(+12
Back to the equation:
-(-1x+(x+3(-1x+4)-2x))*4(+12)
x*4(-1x+12)-(-1x+(x+3(-1x+4)-2x))*412-1=0
Wy multiply elements
4x^2(--(-1x+(x+3(-1x+4)-2x))*412-1=0
We use the square of the difference formula
4x^2(+(-1x+(x+3(-1x+4)-2x))*412-1=0
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