x-1/4x=5/4x-4

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Solution for x-1/4x=5/4x-4 equation:



x-1/4x=5/4x-4
We move all terms to the left:
x-1/4x-(5/4x-4)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 4x-4)!=0
x∈R
We get rid of parentheses
x-1/4x-5/4x+4=0
We multiply all the terms by the denominator
x*4x+4*4x-1-5=0
We add all the numbers together, and all the variables
x*4x+4*4x-6=0
Wy multiply elements
4x^2+16x-6=0
a = 4; b = 16; c = -6;
Δ = b2-4ac
Δ = 162-4·4·(-6)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{22}}{2*4}=\frac{-16-4\sqrt{22}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{22}}{2*4}=\frac{-16+4\sqrt{22}}{8} $

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