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x-1/5x=100
We move all terms to the left:
x-1/5x-(100)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
x*5x-100*5x-1=0
Wy multiply elements
5x^2-500x-1=0
a = 5; b = -500; c = -1;
Δ = b2-4ac
Δ = -5002-4·5·(-1)
Δ = 250020
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{250020}=\sqrt{36*6945}=\sqrt{36}*\sqrt{6945}=6\sqrt{6945}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-500)-6\sqrt{6945}}{2*5}=\frac{500-6\sqrt{6945}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-500)+6\sqrt{6945}}{2*5}=\frac{500+6\sqrt{6945}}{10} $
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