x-1/6-x-3/2=1

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Solution for x-1/6-x-3/2=1 equation: 


x in (-oo:+oo)

x-x-(1/6)-(3/2) = 1 // - 1

x-x-(1/6)-(3/2)-1 = 0

x-x-1/6-3/2-1 = 0

-8/3 = 0

x belongs to the empty set

x belongs to the empty set

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