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x-10+3x=2(2x-4)-2
We move all terms to the left:
x-10+3x-(2(2x-4)-2)=0
We add all the numbers together, and all the variables
4x-(2(2x-4)-2)-10=0
We calculate terms in parentheses: -(2(2x-4)-2), so:We get rid of parentheses
2(2x-4)-2
We multiply parentheses
4x-8-2
We add all the numbers together, and all the variables
4x-10
Back to the equation:
-(4x-10)
4x-4x+10-10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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