x-10=7(2x+3)-5

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Solution for x-10=7(2x+3)-5 equation: 



x-10=7(2x+3)-5

We move all terms to the left:

x-10-(7(2x+3)-5)=0



We calculate terms in parentheses: -(7(2x+3)-5), so:

7(2x+3)-5

We multiply parentheses

14x+21-5

We add all the numbers together, and all the variables

14x+16

Back to the equation:

-(14x+16)



We get rid of parentheses

x-14x-16-10=0

We add all the numbers together, and all the variables

-13x-26=0

We move all terms containing x to the left, all other terms to the right

-13x=26

x=26/-13

x=-2

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