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x-11/10x=15
We move all terms to the left:
x-11/10x-(15)=0
Domain of the equation: 10x!=0We multiply all the terms by the denominator
x!=0/10
x!=0
x∈R
x*10x-15*10x-11=0
Wy multiply elements
10x^2-150x-11=0
a = 10; b = -150; c = -11;
Δ = b2-4ac
Δ = -1502-4·10·(-11)
Δ = 22940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{22940}=\sqrt{4*5735}=\sqrt{4}*\sqrt{5735}=2\sqrt{5735}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-2\sqrt{5735}}{2*10}=\frac{150-2\sqrt{5735}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+2\sqrt{5735}}{2*10}=\frac{150+2\sqrt{5735}}{20} $
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