x-116=8(2x+3)-20

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Solution for x-116=8(2x+3)-20 equation: 



x-116=8(2x+3)-20

We move all terms to the left:

x-116-(8(2x+3)-20)=0



We calculate terms in parentheses: -(8(2x+3)-20), so:

8(2x+3)-20

We multiply parentheses

16x+24-20

We add all the numbers together, and all the variables

16x+4

Back to the equation:

-(16x+4)



We get rid of parentheses

x-16x-4-116=0

We add all the numbers together, and all the variables

-15x-120=0

We move all terms containing x to the left, all other terms to the right

-15x=120

x=120/-15

x=-8

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