If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x-11=2(8+2x)
We move all terms to the left:
x-11-(2(8+2x))=0
We add all the numbers together, and all the variables
x-(2(2x+8))-11=0
We calculate terms in parentheses: -(2(2x+8)), so:We get rid of parentheses
2(2x+8)
We multiply parentheses
4x+16
Back to the equation:
-(4x+16)
x-4x-16-11=0
We add all the numbers together, and all the variables
-3x-27=0
We move all terms containing x to the left, all other terms to the right
-3x=27
x=27/-3
x=-9
| (D^2+6D+9)y=0 | | h-(-41)/8=9 | | 1/3x2-40=-13 | | 4^x+1=5^2x | | 10-6s=-7s | | 4x2-2=34 | | 23-3x=2 | | 5x2=245 | | 2x-9x=-28+10 | | 29=9x+2 | | 5x-1/3=6/x= | | 29=9x=2 | | -38=x/8+-45 | | 71.00+x=81.17 | | 12+6=8x-10 | | (D^2+16)y=0 | | 4x+0.50=3 | | -3-5(3x+7=0 | | 9x-13=67 | | -6d=-8d–4 | | 71.00+x=81.87 | | 9x-(-13)=67 | | 6p–9=7p | | 18x+48=6x+50 | | 9m=-6+10m | | 7/3-2(x-10)/3=3(x-4)/5 | | 4^2x^2+2x=8 | | 3x4.6=14 | | 2x^2(-x+1)+16(x-2)=0 | | 32=x/7+27 | | (D^2+2D-15)y=0 | | 39-(2c+4)=2(c+5+c |