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x-12+4/3x=90
We move all terms to the left:
x-12+4/3x-(90)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x+4/3x-102=0
We multiply all the terms by the denominator
x*3x-102*3x+4=0
Wy multiply elements
3x^2-306x+4=0
a = 3; b = -306; c = +4;
Δ = b2-4ac
Δ = -3062-4·3·4
Δ = 93588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{93588}=\sqrt{4*23397}=\sqrt{4}*\sqrt{23397}=2\sqrt{23397}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-306)-2\sqrt{23397}}{2*3}=\frac{306-2\sqrt{23397}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-306)+2\sqrt{23397}}{2*3}=\frac{306+2\sqrt{23397}}{6} $
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