x-12/3-x=x+8/x+12

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Solution for x-12/3-x=x+8/x+12 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-x-(12/3) = x+8/x+12 // - x+8/x+12

x-x-x-(8/x)-(12/3)-12 = 0

x-x-x-8*x^-1-12-4 = 0

-1*x^1-8*x^-1-16*x^0 = 0

(-1*x^2-16*x^1-8*x^0)/(x^1) = 0 // * x^2

x^1*(-1*x^2-16*x^1-8*x^0) = 0

x^1

-x^2-16*x-8 = 0

-x^2-16*x-8 = 0

DELTA = (-16)^2-(-8*(-1)*4)

DELTA = 224

DELTA > 0

x = (224^(1/2)+16)/(-1*2) or x = (16-224^(1/2))/(-1*2)

x = (4*14^(1/2)+16)/(-2) or x = (16-4*14^(1/2))/(-2)

x in { (4*14^(1/2)+16)/(-2), (16-4*14^(1/2))/(-2)} 

x in { (4*14^(1/2)+16)/(-2), (16-4*14^(1/2))/(-2) }

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