x-2(1-2x)=3(j-3)+5

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Solution for x-2(1-2x)=3(j-3)+5 equation: 


Simplifying
x + -2(1 + -2x) = 3(j + -3) + 5
x + (1 * -2 + -2x * -2) = 3(j + -3) + 5
x + (-2 + 4x) = 3(j + -3) + 5

Reorder the terms:
-2 + x + 4x = 3(j + -3) + 5

Combine like terms: x + 4x = 5x
-2 + 5x = 3(j + -3) + 5

Reorder the terms:
-2 + 5x = 3(-3 + j) + 5
-2 + 5x = (-3 * 3 + j * 3) + 5
-2 + 5x = (-9 + 3j) + 5

Reorder the terms:
-2 + 5x = -9 + 5 + 3j

Combine like terms: -9 + 5 = -4
-2 + 5x = -4 + 3j

Solving
-2 + 5x = -4 + 3j

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 5x = -4 + 2 + 3j

Combine like terms: -2 + 2 = 0
0 + 5x = -4 + 2 + 3j
5x = -4 + 2 + 3j

Combine like terms: -4 + 2 = -2
5x = -2 + 3j

Divide each side by '5'.
x = -0.4 + 0.6j

Simplifying
x = -0.4 + 0.6j

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