x-2(2-3/2x)=2(4-x)+10

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Solution for x-2(2-3/2x)=2(4-x)+10 equation: 



x-2(2-3/2x)=2(4-x)+10

We move all terms to the left:

x-2(2-3/2x)-(2(4-x)+10)=0



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

x-2(-3/2x+2)-(2(-1x+4)+10)=0

We multiply parentheses

x+6x-(2(-1x+4)+10)-4=0



We calculate terms in parentheses: -(2(-1x+4)+10), so:

2(-1x+4)+10

We multiply parentheses

-2x+8+10

We add all the numbers together, and all the variables

-2x+18

Back to the equation:

-(-2x+18)



We add all the numbers together, and all the variables

7x-(-2x+18)-4=0

We get rid of parentheses

7x+2x-18-4=0

We add all the numbers together, and all the variables

9x-22=0

We move all terms containing x to the left, all other terms to the right

9x=22

x=22/9

x=2+4/9

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