x-2(2-32x)=2(4-x)+10

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Solution for x-2(2-32x)=2(4-x)+10 equation: 



x-2(2-32x)=2(4-x)+10

We move all terms to the left:

x-2(2-32x)-(2(4-x)+10)=0

We add all the numbers together, and all the variables

x-2(-32x+2)-(2(-1x+4)+10)=0

We multiply parentheses

x+64x-(2(-1x+4)+10)-4=0



We calculate terms in parentheses: -(2(-1x+4)+10), so:

2(-1x+4)+10

We multiply parentheses

-2x+8+10

We add all the numbers together, and all the variables

-2x+18

Back to the equation:

-(-2x+18)



We add all the numbers together, and all the variables

65x-(-2x+18)-4=0

We get rid of parentheses

65x+2x-18-4=0

We add all the numbers together, and all the variables

67x-22=0

We move all terms containing x to the left, all other terms to the right

67x=22

x=22/67

x=22/67

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