x-2(x+1)+3(x-2)+2(x-6=0

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Solution for x-2(x+1)+3(x-2)+2(x-6=0 equation: 



x-2(x+1)+3(x-2)+2(x-6=0

We multiply parentheses

x-2x+3x+2(x-6-2-6=0

We add all the numbers together, and all the variables

2x+2(x-6-2-6=0

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