x-2(x+1)=12-6(3x-2)

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Solution for x-2(x+1)=12-6(3x-2) equation: 



x-2(x+1)=12-6(3x-2)

We move all terms to the left:

x-2(x+1)-(12-6(3x-2))=0

We multiply parentheses

x-2x-(12-6(3x-2))-2=0



We calculate terms in parentheses: -(12-6(3x-2)), so:

12-6(3x-2)

determiningTheFunctionDomain
-6(3x-2)+12

We multiply parentheses

-18x+12+12

We add all the numbers together, and all the variables

-18x+24

Back to the equation:

-(-18x+24)



We add all the numbers together, and all the variables

-1x-(-18x+24)-2=0

We get rid of parentheses

-1x+18x-24-2=0

We add all the numbers together, and all the variables

17x-26=0

We move all terms containing x to the left, all other terms to the right

17x=26

x=26/17

x=1+9/17

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