x-2(x+10)=9(x+3)+5

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Solution for x-2(x+10)=9(x+3)+5 equation: 



x-2(x+10)=9(x+3)+5

We move all terms to the left:

x-2(x+10)-(9(x+3)+5)=0

We multiply parentheses

x-2x-(9(x+3)+5)-20=0



We calculate terms in parentheses: -(9(x+3)+5), so:

9(x+3)+5

We multiply parentheses

9x+27+5

We add all the numbers together, and all the variables

9x+32

Back to the equation:

-(9x+32)



We add all the numbers together, and all the variables

-1x-(9x+32)-20=0

We get rid of parentheses

-1x-9x-32-20=0

We add all the numbers together, and all the variables

-10x-52=0

We move all terms containing x to the left, all other terms to the right

-10x=52

x=52/-10

x=-5+1/5

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