x-2(x+2)=8+x

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Solution for x-2(x+2)=8+x equation:



x-2(x+2)=8+x
We move all terms to the left:
x-2(x+2)-(8+x)=0
We add all the numbers together, and all the variables
x-2(x+2)-(x+8)=0
We multiply parentheses
x-2x-(x+8)-4=0
We get rid of parentheses
x-2x-x-8-4=0
We add all the numbers together, and all the variables
-2x-12=0
We move all terms containing x to the left, all other terms to the right
-2x=12
x=12/-2
x=-6

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