x-2(x+2)=8+x

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Solution for x-2(x+2)=8+x equation: 



x-2(x+2)=8+x

We move all terms to the left:

x-2(x+2)-(8+x)=0

We add all the numbers together, and all the variables

x-2(x+2)-(x+8)=0

We multiply parentheses

x-2x-(x+8)-4=0

We get rid of parentheses

x-2x-x-8-4=0

We add all the numbers together, and all the variables

-2x-12=0

We move all terms containing x to the left, all other terms to the right

-2x=12

x=12/-2

x=-6

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