x-2(x+3)=4(2x+3)-(x-4)

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Solution for x-2(x+3)=4(2x+3)-(x-4) equation:



x-2(x+3)=4(2x+3)-(x-4)
We move all terms to the left:
x-2(x+3)-(4(2x+3)-(x-4))=0
We multiply parentheses
x-2x-(4(2x+3)-(x-4))-6=0
We calculate terms in parentheses: -(4(2x+3)-(x-4)), so:
4(2x+3)-(x-4)
We multiply parentheses
8x-(x-4)+12
We get rid of parentheses
8x-x+4+12
We add all the numbers together, and all the variables
7x+16
Back to the equation:
-(7x+16)
We add all the numbers together, and all the variables
-1x-(7x+16)-6=0
We get rid of parentheses
-1x-7x-16-6=0
We add all the numbers together, and all the variables
-8x-22=0
We move all terms containing x to the left, all other terms to the right
-8x=22
x=22/-8
x=-2+3/4

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