x-2(x-5)+1=2x-3-2(x+1)

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Solution for x-2(x-5)+1=2x-3-2(x+1) equation: 



x-2(x-5)+1=2x-3-2(x+1)

We move all terms to the left:

x-2(x-5)+1-(2x-3-2(x+1))=0

We multiply parentheses

x-2x-(2x-3-2(x+1))+10+1=0



We calculate terms in parentheses: -(2x-3-2(x+1)), so:

2x-3-2(x+1)

determiningTheFunctionDomain
2x-2(x+1)-3

We multiply parentheses

2x-2x-2-3

We add all the numbers together, and all the variables

-5

Back to the equation:

-(-5)



We add all the numbers together, and all the variables

-1x+16=0

We move all terms containing x to the left, all other terms to the right

-x=-16

x=-16/-1

x=+16

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