x-2(x-5)=3(2x-4)

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Solution for x-2(x-5)=3(2x-4) equation: 



x-2(x-5)=3(2x-4)

We move all terms to the left:

x-2(x-5)-(3(2x-4))=0

We multiply parentheses

x-2x-(3(2x-4))+10=0



We calculate terms in parentheses: -(3(2x-4)), so:

3(2x-4)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

-1x-(6x-12)+10=0

We get rid of parentheses

-1x-6x+12+10=0

We add all the numbers together, and all the variables

-7x+22=0

We move all terms containing x to the left, all other terms to the right

-7x=-22

x=-22/-7

x=3+1/7

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