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x-2/2+x-2(x-4)/6=x/3
We move all terms to the left:
x-2/2+x-2(x-4)/6-(x/3)=0
We add all the numbers together, and all the variables
x+x-2(x-4)/6-(+x/3)-2/2=0
We add all the numbers together, and all the variables
2x-2(x-4)/6-(+x/3)-1=0
We get rid of parentheses
2x-2(x-4)/6-x/3-1=0
We calculate fractions
There is no solution for this equation
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