x-2/2x+1=x+3/x

Solution for x-2/2x+1=x+3/x equation:

x-2/2x+1=x+3/x

We move all terms to the left:

x-2/2x+1-(x+3/x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x-2/2x-(+x+3/x)+1=0

We get rid of parentheses

x-2/2x-x-3/x+1=0

We calculate fractions


x-x+(-2x)/2x^2+(-6x)/2x^2+1=0

We add all the numbers together, and all the variables

(-2x)/2x^2+(-6x)/2x^2+1=0

We multiply all the terms by the denominator


(-2x)+(-6x)+1*2x^2=0

Wy multiply elements

2x^2+(-2x)+(-6x)=0

We get rid of parentheses

2x^2-2x-6x=0

We add all the numbers together, and all the variables

2x^2-8x=0

a = 2; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·2·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*2}=\frac{16}{4}
=4
$