x-2/3x+16=25

Solution for x-2/3x+16=25 equation:

x-2/3x+16=25

We move all terms to the left:

x-2/3x+16-(25)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

x-2/3x-9=0

We multiply all the terms by the denominator


x*3x-9*3x-2=0

Wy multiply elements

3x^2-27x-2=0

a = 3; b = -27; c = -2;
Δ = b2-4ac
Δ = -272-4·3·(-2)
Δ = 753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{753}}{2*3}=\frac{27-\sqrt{753}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{753}}{2*3}=\frac{27+\sqrt{753}}{6}
$