If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
x-(2/4) = x/1+1 // - x/1+1
x-(x/1)-(2/4)-1 = 0
x-x-1/2-1 = 0
-3/2 = 0
x belongs to the empty set
x belongs to the empty set
| x^2+3x+5=7 | | 2x-6=10-6x | | (4x-1)/3=7/1 | | x/x=1.816 | | x/x | | 10-2x=96 | | 18-3(x-2)=21 | | 30t/(30+11t)=2 | | 180/3x=100 | | s^2-13s+30=0 | | 3x+1=70 | | -7t+2t-9=30-12 | | s^2-16x=0 | | 7m+3m=93 | | 32-2x=16 | | 3x-2(x-2)=4(x-1)-2(x+2)+3 | | 32-2x=10 | | 9/2x+2=8/x | | 36s^2=9 | | 120-35x=375 | | 120+35x=375 | | 6-9x=19-16x | | 3x-5=2(4-x)-1 | | -x/6=24 | | -4(x+4)=-7x-10 | | 20-5P=-10+10P | | 114-7x=20x+118 | | (7/4a^2-3/2a+6)-(1/12a+3/4a+2) | | x-4=-9x+x | | 6(-5x+2)=108 | | 6-8x=82-22x | | 2x^3-6x^2-90=0 |