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x-2/5x=510
We move all terms to the left:
x-2/5x-(510)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
x*5x-510*5x-2=0
Wy multiply elements
5x^2-2550x-2=0
a = 5; b = -2550; c = -2;
Δ = b2-4ac
Δ = -25502-4·5·(-2)
Δ = 6502540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6502540}=\sqrt{484*13435}=\sqrt{484}*\sqrt{13435}=22\sqrt{13435}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2550)-22\sqrt{13435}}{2*5}=\frac{2550-22\sqrt{13435}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2550)+22\sqrt{13435}}{2*5}=\frac{2550+22\sqrt{13435}}{10} $
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