x-2/x-1=x+4/2x+2

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Solution for x-2/x-1=x+4/2x+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-(2/x)-1 = x+(4/2)*x+2 // - x+(4/2)*x+2

x-x-((4/2)*x)-(2/x)-2-1 = 0

x-x-2*x-2*x^-1-2-1 = 0

-2*x^1-2*x^-1-3*x^0 = 0

(-2*x^2-3*x^1-2*x^0)/(x^1) = 0 // * x^2

x^1*(-2*x^2-3*x^1-2*x^0) = 0

x^1

-2*x^2-3*x-2 = 0

-2*x^2-3*x-2 = 0

DELTA = (-3)^2-(-2*(-2)*4)

DELTA = -7

DELTA < 0

x in { } 

x belongs to the empty set

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