x-26+1/3x+13+3x-67=180

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Solution for x-26+1/3x+13+3x-67=180 equation:



x-26+1/3x+13+3x-67=180
We move all terms to the left:
x-26+1/3x+13+3x-67-(180)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
4x+1/3x-260=0
We multiply all the terms by the denominator
4x*3x-260*3x+1=0
Wy multiply elements
12x^2-780x+1=0
a = 12; b = -780; c = +1;
Δ = b2-4ac
Δ = -7802-4·12·1
Δ = 608352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{608352}=\sqrt{16*38022}=\sqrt{16}*\sqrt{38022}=4\sqrt{38022}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-780)-4\sqrt{38022}}{2*12}=\frac{780-4\sqrt{38022}}{24} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-780)+4\sqrt{38022}}{2*12}=\frac{780+4\sqrt{38022}}{24} $

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