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x-2=2(4+x1)
We move all terms to the left:
x-2-(2(4+x1))=0
We add all the numbers together, and all the variables
x-(2(x+4))-2=0
We calculate terms in parentheses: -(2(x+4)), so:We get rid of parentheses
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
x-2x-8-2=0
We add all the numbers together, and all the variables
-1x-10=0
We move all terms containing x to the left, all other terms to the right
-x=10
x=10/-1
x=-10
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