x-2=5(2x+3)-8

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Solution for x-2=5(2x+3)-8 equation:



x-2=5(2x+3)-8
We move all terms to the left:
x-2-(5(2x+3)-8)=0
We calculate terms in parentheses: -(5(2x+3)-8), so:
5(2x+3)-8
We multiply parentheses
10x+15-8
We add all the numbers together, and all the variables
10x+7
Back to the equation:
-(10x+7)
We get rid of parentheses
x-10x-7-2=0
We add all the numbers together, and all the variables
-9x-9=0
We move all terms containing x to the left, all other terms to the right
-9x=9
x=9/-9
x=-1

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