x-2x+2-16x-2=3-7/2x

Solution for x-2x+2-16x-2=3-7/2x equation:

x-2x+2-16x-2=3-7/2x

We move all terms to the left:

x-2x+2-16x-2-(3-7/2x)=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x-2x-16x-(-7/2x+3)+2-2=0

We add all the numbers together, and all the variables

-17x-(-7/2x+3)=0

We get rid of parentheses

-17x+7/2x-3=0

We multiply all the terms by the denominator


-17x*2x-3*2x+7=0

Wy multiply elements

-34x^2-6x+7=0

a = -34; b = -6; c = +7;
Δ = b2-4ac
Δ = -62-4·(-34)·7
Δ = 988
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{988}=\sqrt{4*247}=\sqrt{4}*\sqrt{247}=2\sqrt{247}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{247}}{2*-34}=\frac{6-2\sqrt{247}}{-68}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{247}}{2*-34}=\frac{6+2\sqrt{247}}{-68}
$