x-2x-x+2=(x-2)(x-1)

Solution for x-2x-x+2=(x-2)(x-1) equation:

x-2x-x+2=(x-2)(x-1)

We move all terms to the left:

x-2x-x+2-((x-2)(x-1))=0

We add all the numbers together, and all the variables

-2x-((x-2)(x-1))+2=0

We multiply parentheses ..

-((+x^2-1x-2x+2))-2x+2=0


We calculate terms in parentheses: -((+x^2-1x-2x+2)), so:

(+x^2-1x-2x+2)

We get rid of parentheses

x^2-1x-2x+2

We add all the numbers together, and all the variables

x^2-3x+2

Back to the equation:

-(x^2-3x+2)


We add all the numbers together, and all the variables

-2x-(x^2-3x+2)+2=0

We get rid of parentheses

-x^2-2x+3x-2+2=0

We add all the numbers together, and all the variables

-1x^2+x=0

a = -1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-1)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-1}=\frac{-2}{-2}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-1}=\frac{0}{-2}
=0
$