x-3(2x+2)=7-3(x+1)

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Solution for x-3(2x+2)=7-3(x+1) equation: 



x-3(2x+2)=7-3(x+1)

We move all terms to the left:

x-3(2x+2)-(7-3(x+1))=0

We multiply parentheses

x-6x-(7-3(x+1))-6=0



We calculate terms in parentheses: -(7-3(x+1)), so:

7-3(x+1)

determiningTheFunctionDomain
-3(x+1)+7

We multiply parentheses

-3x-3+7

We add all the numbers together, and all the variables

-3x+4

Back to the equation:

-(-3x+4)



We add all the numbers together, and all the variables

-5x-(-3x+4)-6=0

We get rid of parentheses

-5x+3x-4-6=0

We add all the numbers together, and all the variables

-2x-10=0

We move all terms containing x to the left, all other terms to the right

-2x=10

x=10/-2

x=-5

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