x-3(x+3)=9+2(x-4)

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Solution for x-3(x+3)=9+2(x-4) equation: 



x-3(x+3)=9+2(x-4)

We move all terms to the left:

x-3(x+3)-(9+2(x-4))=0

We multiply parentheses

x-3x-(9+2(x-4))-9=0



We calculate terms in parentheses: -(9+2(x-4)), so:

9+2(x-4)

determiningTheFunctionDomain
2(x-4)+9

We multiply parentheses

2x-8+9

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

-2x-(2x+1)-9=0

We get rid of parentheses

-2x-2x-1-9=0

We add all the numbers together, and all the variables

-4x-10=0

We move all terms containing x to the left, all other terms to the right

-4x=10

x=10/-4

x=-2+1/2

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