x-3(x-3+2x+9)=9(9+3x+2)

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Solution for x-3(x-3+2x+9)=9(9+3x+2) equation:



x-3(x-3+2x+9)=9(9+3x+2)
We move all terms to the left:
x-3(x-3+2x+9)-(9(9+3x+2))=0
We add all the numbers together, and all the variables
x-3(3x+6)-(9(3x+11))=0
We multiply parentheses
x-9x-(9(3x+11))-18=0
We calculate terms in parentheses: -(9(3x+11)), so:
9(3x+11)
We multiply parentheses
27x+99
Back to the equation:
-(27x+99)
We add all the numbers together, and all the variables
-8x-(27x+99)-18=0
We get rid of parentheses
-8x-27x-99-18=0
We add all the numbers together, and all the variables
-35x-117=0
We move all terms containing x to the left, all other terms to the right
-35x=117
x=117/-35
x=-3+12/35

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