If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
x-(3/2)-3 = x-(5/3) // - x-(5/3)
x-x-(3/2)+5/3-3 = 0
x-x-3/2+5/3-3 = 0
-17/6 = 0
x belongs to the empty set
x belongs to the empty set
| y/121=0.55/11 | | -9v+43=-7(v-5) | | z/5-4=12 | | 1/3(x-8)1/8(3x-1) | | 4y-7+y+57=5y+50-2y | | 2x+3=9x+21 | | -2/7=-1u/3-1/2 | | 3w-12=21 | | 3x+12=11x+2 | | 4x=1/8 | | -15=-5/7x | | (28x^2-5x-13)=0 | | 6u+2-3(-4u-4)=4(u-1) | | 0.08t+0.11(t+200)=117 | | 60=35-5(x-1) | | 238=40-y | | 6x^3+18x^2-x+24=0 | | 5(y-5)=7y-5 | | x+4.1=10.1 | | x-3/4=-1/5 | | 28x^2-5x-13=0 | | 11=-7u+3(u-3) | | 8+2x(4)=5x+11 | | log^2(3x-9)=4 | | x(3x-5)=(3x+8)(x-3) | | y=0.20x+60 | | 9x+2x-6x=9+1 | | 5+14m-4=8m+41-2m | | 90-8.36x=39.84 | | (6x)(x-6)=0 | | 73-(4x+10)=4(x+9)+x | | 2x-18=-48 |