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x-3/3x-1=1
We move all terms to the left:
x-3/3x-1-(1)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x-3/3x-2=0
We multiply all the terms by the denominator
x*3x-2*3x-3=0
Wy multiply elements
3x^2-6x-3=0
a = 3; b = -6; c = -3;
Δ = b2-4ac
Δ = -62-4·3·(-3)
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{2}}{2*3}=\frac{6-6\sqrt{2}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{2}}{2*3}=\frac{6+6\sqrt{2}}{6} $
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