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x-3/x+3+x+3/x-3=2*0.5
We move all terms to the left:
x-3/x+3+x+3/x-3-(2*0.5)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
x-3/x+x+3/x+3-3-1=0
We add all the numbers together, and all the variables
2x-3/x+3/x-1=0
We multiply all the terms by the denominator
2x*x-1*x-3+3=0
We add all the numbers together, and all the variables
-1x+2x*x=0
Wy multiply elements
2x^2-1x=0
a = 2; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*2}=\frac{0}{4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*2}=\frac{2}{4} =1/2 $
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