x-3/x+6=10/2

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Solution for x-3/x+6=10/2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-(3/x)+6 = 10/2 // - 10/2

x-(3/x)-(10/2)+6 = 0

x-3*x^-1-5+6 = 0

1*x^1-3*x^-1+1*x^0 = 0

(1*x^2+1*x^1-3*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+1*x^1-3*x^0) = 0

x^1

x^2+x-3 = 0

x^2+x-3 = 0

DELTA = 1^2-(-3*1*4)

DELTA = 13

DELTA > 0

x = (13^(1/2)-1)/(1*2) or x = (-13^(1/2)-1)/(1*2)

x = (13^(1/2)-1)/2 or x = (-(13^(1/2)+1))/2

x in { (-(13^(1/2)+1))/2, (13^(1/2)-1)/2} 

x in { (-(13^(1/2)+1))/2, (13^(1/2)-1)/2 }

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