x-3/x-2=+1/x-2

Solution for x-3/x-2=+1/x-2 equation:

x-3/x-2=+1/x-2

We move all terms to the left:

x-3/x-2-(+1/x-2)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: x-2)!=0

x∈R


We add all the numbers together, and all the variables

x-3/x-(1/x-2)-2=0

We get rid of parentheses

x-3/x-1/x+2-2=0

We multiply all the terms by the denominator


x*x+2*x-2*x-3-1=0

We add all the numbers together, and all the variables

x*x-4=0

Wy multiply elements

x^2-4=0

a = 1; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·1·(-4)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*1}=\frac{-4}{2}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*1}=\frac{4}{2}
=2
$