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x-3/x-4=2x/x+2
We move all terms to the left:
x-3/x-4-(2x/x+2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x+2)!=0We get rid of parentheses
x∈R
x-3/x-2x/x-2-4=0
We multiply all the terms by the denominator
x*x-2x-2*x-4*x-3=0
We add all the numbers together, and all the variables
-8x+x*x-3=0
Wy multiply elements
x^2-8x-3=0
a = 1; b = -8; c = -3;
Δ = b2-4ac
Δ = -82-4·1·(-3)
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{19}}{2*1}=\frac{8-2\sqrt{19}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{19}}{2*1}=\frac{8+2\sqrt{19}}{2} $
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