x-36+1/2x+18+3x-72=180

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Solution for x-36+1/2x+18+3x-72=180 equation:



x-36+1/2x+18+3x-72=180
We move all terms to the left:
x-36+1/2x+18+3x-72-(180)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
4x+1/2x-270=0
We multiply all the terms by the denominator
4x*2x-270*2x+1=0
Wy multiply elements
8x^2-540x+1=0
a = 8; b = -540; c = +1;
Δ = b2-4ac
Δ = -5402-4·8·1
Δ = 291568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{291568}=\sqrt{16*18223}=\sqrt{16}*\sqrt{18223}=4\sqrt{18223}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-540)-4\sqrt{18223}}{2*8}=\frac{540-4\sqrt{18223}}{16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-540)+4\sqrt{18223}}{2*8}=\frac{540+4\sqrt{18223}}{16} $

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