x-3=(8x/9)+4

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Solution for x-3=(8x/9)+4 equation:



x-3=(8x/9)+4
We move all terms to the left:
x-3-((8x/9)+4)=0
We add all the numbers together, and all the variables
x-((+8x/9)+4)-3=0
We multiply all the terms by the denominator
x*9)+4)-((+8x-3*9)+4)=0
We add all the numbers together, and all the variables
x*9)+4)-((8x-27)+4)=0
We add all the numbers together, and all the variables
x*9)+4)-((8x=0
Wy multiply elements
9x^2=0
a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{18}=0$

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