x-3=25-2(-5x)+x*x

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Solution for x-3=25-2(-5x)+x*x equation:


Simplifying
x + -3 = 25 + -2(-5x) + x * x

Reorder the terms:
-3 + x = 25 + -2(-5x) + x * x

Remove parenthesis around (-5x)
-3 + x = 25 + -2 * -5x + x * x

Multiply -2 * -5
-3 + x = 25 + 10x + x * x

Multiply x * x
-3 + x = 25 + 10x + x2

Solving
-3 + x = 25 + 10x + x2

Solving for variable 'x'.

Reorder the terms:
-3 + -25 + x + -10x + -1x2 = 25 + 10x + x2 + -25 + -10x + -1x2

Combine like terms: -3 + -25 = -28
-28 + x + -10x + -1x2 = 25 + 10x + x2 + -25 + -10x + -1x2

Combine like terms: x + -10x = -9x
-28 + -9x + -1x2 = 25 + 10x + x2 + -25 + -10x + -1x2

Reorder the terms:
-28 + -9x + -1x2 = 25 + -25 + 10x + -10x + x2 + -1x2

Combine like terms: 25 + -25 = 0
-28 + -9x + -1x2 = 0 + 10x + -10x + x2 + -1x2
-28 + -9x + -1x2 = 10x + -10x + x2 + -1x2

Combine like terms: 10x + -10x = 0
-28 + -9x + -1x2 = 0 + x2 + -1x2
-28 + -9x + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-28 + -9x + -1x2 = 0

Factor out the Greatest Common Factor (GCF), '-1'.
-1(28 + 9x + x2) = 0

Ignore the factor -1.

Subproblem 1

Set the factor '(28 + 9x + x2)' equal to zero and attempt to solve: Simplifying 28 + 9x + x2 = 0 Solving 28 + 9x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '-28' to each side of the equation. 28 + 9x + -28 + x2 = 0 + -28 Reorder the terms: 28 + -28 + 9x + x2 = 0 + -28 Combine like terms: 28 + -28 = 0 0 + 9x + x2 = 0 + -28 9x + x2 = 0 + -28 Combine like terms: 0 + -28 = -28 9x + x2 = -28 The x term is 9x. Take half its coefficient (4.5). Square it (20.25) and add it to both sides. Add '20.25' to each side of the equation. 9x + 20.25 + x2 = -28 + 20.25 Reorder the terms: 20.25 + 9x + x2 = -28 + 20.25 Combine like terms: -28 + 20.25 = -7.75 20.25 + 9x + x2 = -7.75 Factor a perfect square on the left side: (x + 4.5)(x + 4.5) = -7.75 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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