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x-3x/x+2=6/x+2
We move all terms to the left:
x-3x/x+2-(6/x+2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x+2)!=0We get rid of parentheses
x∈R
x-3x/x-6/x-2+2=0
We multiply all the terms by the denominator
x*x-3x-2*x+2*x-6=0
We add all the numbers together, and all the variables
-3x+x*x-6=0
Wy multiply elements
x^2-3x-6=0
a = 1; b = -3; c = -6;
Δ = b2-4ac
Δ = -32-4·1·(-6)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{33}}{2*1}=\frac{3-\sqrt{33}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{33}}{2*1}=\frac{3+\sqrt{33}}{2} $
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